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Python format date iso

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I.m getting a datetime string in a format like "2009-05-28T16:15:00" (this is ISO 8601 I believe) one hack-ish option seems to be to parse the string using. I would use the datetime module to parse it: >>> from datetime import datetime >> > date = datetime.strptime(.2/28/1987.%m/%d/%Y.). In Python, I would like to take its creation time, and convert it to an ISO I found the datetime.isoformat in the doc. seems to do what you want.

I need to parse strings like "2008-09-03T20:56:35.450686Z" into As Alexander mentioned, it seems that python-dateutil works very well. You need to make your datetime objects timezone aware. from the datetime docs: There are two kinds of date and time objects: “naive” and “aware”.

Python format date iso

The international standard ISO 8601 describes a string representation for dates This format is of course not Python specific, but it is good for storing dates and. This example prints the current date in several formats: $ python. The default string representation of a datetime object uses the ISO 8601 format.

How do I translate a ISO 8601 datetime string into a Python

Fully implemented, drop-in replacement for datetime. Supports Python 2.6, 2.7. Many ISO-8601 compliant strings are recognized and parsed without a format. Python datetime-example-1.py 2003-08-04 12:30:45 datetime.datetime(2003, 8, 4 Note that the default string representation is an ISO 8601-style timestamp.

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